# Van Aubel theorem

Let $ABC$ be a triangle and $AD,BE,CF$ concurrent^{} cevians at $P$.

Then

$$\frac{CP}{PF}=\frac{CD}{DB}+\frac{CE}{EA}$$ |

Title | Van Aubel theorem^{} |
---|---|

Canonical name | VanAubelTheorem |

Date of creation | 2013-03-22 14:03:26 |

Last modified on | 2013-03-22 14:03:26 |

Owner | drini (3) |

Last modified by | drini (3) |

Numerical id | 7 |

Author | drini (3) |

Entry type | Theorem |

Classification | msc 51N20 |

Related topic | ProofOfVanAubelsTheorem |

Related topic | CevasTheorem |

Related topic | VanAubelsTheorem |

Related topic | ProofOfVanAubelTheorem |

Related topic | TrigonometricVersionOfCevasTheorem |