Consider the integer 384. Multiplying its digits,
All 1-digit numbers and the base number itself are Zuckerman numbers.
It is possible for an integer to be divisible by its multiplicative digital root and yet not be a Zuckerman number because it doesn’t divide its first digit product evenly (for example, 1728 in base 10 has multiplicative digital root 2 but is not divisible by ). The reverse is also possible (for example, 384 is divisible by 96, as shown above, but clearly not by its multiplicative digital root 0).
- 1 J. J. Tattersall, Elementary number theory in nine chapters, p. 86. Cambridge: Cambridge University Press (2005)
|Date of creation||2013-03-22 16:04:36|
|Last modified on||2013-03-22 16:04:36|
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