derivative operator is unbounded in the sup norm
This space admits a norm called the supremum norm given by
This norm makes this vector space into a metric space.
All we need to prove is that there exists a succession of functions such that is divergent as
So we finally get
showing that the derivative operator is indeed unbounded since is divergent as .
|Title||derivative operator is unbounded in the sup norm|
|Date of creation||2013-07-14 20:22:55|
|Last modified on||2013-07-14 20:22:55|
|Last modified by||cvalente (11260)|