generalized Riemann-Lebesgue lemma
Generalized Riemann-Lebesgue lemmaFernando Sanz Gamiz
Obviously we only need to prove the lemma when both and are real and .
Now let be a bound for and choose . As step functions are dense in , we can find, for any , a step function such that , therefore
because by what we have proved for step functions. Since is arbitrary, we are done.
|Title||generalized Riemann-Lebesgue lemma|
|Date of creation||2013-03-22 17:06:03|
|Last modified on||2013-03-22 17:06:03|
|Last modified by||fernsanz (8869)|