# sines law

Let $ABC$ be a triangle where $a,b,c$ are the sides opposite to $A,B,C$ respectively, and let $R$ be the radius of the circumcircle. Then the following relation holds:

 $\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}=2R.$
Title sines law SinesLaw 2013-03-22 11:42:40 2013-03-22 11:42:40 drini (3) drini (3) 26 drini (3) Theorem msc 51-00 msc 97-01 law of sines CosinesLaw SinesLawProof Triangle