fundamental theorem of coalgebras
Fundamental Theorem of Coalgebras. Let be a coalgebra over a field and . Then there exists subcoalgebra such that and .
Proof. Let
Consider the element
Note that we may assume that are linearly independent![]()
and so are . Let be a subspace
spanned by . Of course . Furthermore , because
We will show that is a subcoalgebra, i.e. . Indeed, note that
and since are linearly independent we obtain that
for all . Thus
and since are linearly independent, we obtain that for all . Analogously we show that , thus
(please, see this entry (http://planetmath.org/TensorProductOfSubspacesOfVectorSpaces) for last equality) which completes the proof.
Remark. The category of finite dimensional coalgebras is dual to the category of finite dimensional algebras![]()
(via dual space
functor), so one could think that generally they are similar
. Unfortunetly Fundamental Theorem of Coalgebras is major diffrence between algebras and coalgebras. For example consider a field and its polynomial algebra . Then whenever is such that , then a subalgebra generated by is always infinite dimensional (if then subalgebra generated by is ). This can never occur in coalgebras.
| Title | fundamental theorem of coalgebras |
|---|---|
| Canonical name | FundamentalTheoremOfCoalgebras |
| Date of creation | 2013-03-22 18:49:22 |
| Last modified on | 2013-03-22 18:49:22 |
| Owner | joking (16130) |
| Last modified by | joking (16130) |
| Numerical id | 6 |
| Author | joking (16130) |
| Entry type | Theorem |
| Classification | msc 16W30 |