lemma on projection of countable sets
Suppose is an infinite field and is an infinite subset of
. Then there exists a line such that the projection![]()
of
on is infinite.
Proof: This proof will proceed by an induction on . The case
is trivial since a one-dimensional linear space is a line.
Consider two cases:
Case I: There exists a proper subspace of
which contains an infinite number of points of .
In this case, we can restrict attention to this subspace. By the induction hypothesis, there exists a line in the subspace such that the projection of points in the subspace to this line is already infinite.
Case II: Every proper subspace of contains at most a finite number of points of .
In this case, any line will do. By definition, one constructs a
projection by dropping hyperplanes![]()
perpendicular
![]()
to the line passing
through the points of the set. Since each of these hyperplanes will
contain a finite number of elements of , an infinite number of
hyperplanes will be needed to contain all the points of , hence the
projection will be infinite.
| Title | lemma on projection of countable sets |
|---|---|
| Canonical name | LemmaOnProjectionOfCountableSets |
| Date of creation | 2013-03-22 15:44:53 |
| Last modified on | 2013-03-22 15:44:53 |
| Owner | rspuzio (6075) |
| Last modified by | rspuzio (6075) |
| Numerical id | 10 |
| Author | rspuzio (6075) |
| Entry type | Theorem |
| Classification | msc 14A10 |