lemma on projection of countable sets
Suppose 𝔽 is an infinite field and S is an infinite subset of
𝔽n. Then there exists a line L such that the projection of S
on L is infinite.
Proof: This proof will proceed by an induction on n. The case
n=1 is trivial since a one-dimensional linear space is a line.
Consider two cases:
Case I: There exists a proper subspace of 𝔽n
which contains an infinite number of points of S.
In this case, we can restrict attention to this subspace. By the induction hypothesis, there exists a line in the subspace such that the projection of points in the subspace to this line is already infinite.
Case II: Every proper subspace of 𝔽n contains at most a finite number of points of S.
In this case, any line will do. By definition, one constructs a
projection by dropping hyperplanes perpendicular
to the line passing
through the points of the set. Since each of these hyperplanes will
contain a finite number of elements of S, an infinite number of
hyperplanes will be needed to contain all the points of S, hence the
projection will be infinite.
Title | lemma on projection of countable sets |
---|---|
Canonical name | LemmaOnProjectionOfCountableSets |
Date of creation | 2013-03-22 15:44:53 |
Last modified on | 2013-03-22 15:44:53 |
Owner | rspuzio (6075) |
Last modified by | rspuzio (6075) |
Numerical id | 10 |
Author | rspuzio (6075) |
Entry type | Theorem |
Classification | msc 14A10 |