proof of Euler-Fermat theorem
Let be all positive integers less than which are coprime![]()
to . Since , then the set are each congruent
![]()
to one of the integers in some order. Taking the product
of these congruences
![]()
, we get
hence
Since , we can divide both sides by , and the desired result follows.
| Title | proof of Euler-Fermat theorem |
|---|---|
| Canonical name | ProofOfEulerFermatTheorem |
| Date of creation | 2013-03-22 11:47:57 |
| Last modified on | 2013-03-22 11:47:57 |
| Owner | KimJ (5) |
| Last modified by | KimJ (5) |
| Numerical id | 10 |
| Author | KimJ (5) |
| Entry type | Proof |
| Classification | msc 11A07 |
| Classification | msc 11A25 |