proof of Marty’s theorem
Let be a region with and let be the curves connecting the points . Then we have:
Thus is Lipschitz continuous and thus is equicontinuous. By the Ascoli-ArzelÃÂ Theorem we conclude that is normal.
(ii) Now assume to be normal. Define:
Let be compact. To obtain contradiction assume is not uniformly bounded on . But then there exists a sequence such that:
Since is normal for each let there be a neighbourhood such that converges normally to a meromorphic function . But from we see that converges normally on . Since is compact it can be covered by finitely many sets . We conclude that must be bounded on and obtain a contradiction. ∎
Title | proof of Marty’s theorem |
---|---|
Canonical name | ProofOfMartysTheorem |
Date of creation | 2013-03-22 18:23:11 |
Last modified on | 2013-03-22 18:23:11 |
Owner | karstenb (16623) |
Last modified by | karstenb (16623) |
Numerical id | 4 |
Author | karstenb (16623) |
Entry type | Proof |
Classification | msc 30D30 |