resolvent function is analytic
Theorem - Let be a complex Banach algebra![]()
with identity element
![]()
. Let and denote its spectrum.
Then, the resolvent function (http://planetmath.org/ResolventMatrix) defined by is analytic (http://planetmath.org/BanachSpaceValuedAnalyticFunctions).
Moreover, for each it has the power series
| (1) |
where the series converges absolutely for each in the open disk centered in given by
| (2) |
Proof : Analyticity is defined for functions whose domain is open.
Thus, we start by proving that is an open set in . To do so it is enough to prove that for every the open disk defined by (2) above is contained in .
Let and be such that
Then and by the Neumann series (http://planetmath.org/NeumannSeriesInBanachAlgebras) is invertible.
Since it follows that is invertible.
Hence, from the equality
| (3) |
we conclude that is also invertible, i.e. . Thus is open.
The above proof also pointed out that for every , is defined in the open disk of radius centered in .
We now prove the analyticity of the .
Taking inverses![]()
on the equality (3) above one obtains
Again, by the Neumann series (http://planetmath.org/NeumannSeriesInBanachAlgebras), one obtains
| Title | resolvent function is analytic |
|---|---|
| Canonical name | ResolventFunctionIsAnalytic |
| Date of creation | 2013-03-22 17:29:36 |
| Last modified on | 2013-03-22 17:29:36 |
| Owner | asteroid (17536) |
| Last modified by | asteroid (17536) |
| Numerical id | 8 |
| Author | asteroid (17536) |
| Entry type | Theorem |
| Classification | msc 46H05 |
| Classification | msc 47A10 |