absolute convergence of integral and boundedness of derivative
Theorem. Assume that we have an http://planetmath.org/node/11865absolutely converging integral
where the real function and its derivative are continuous and additionally bounded on the interval . Then
(1) |
Proof. If , we obtain
from which
(2) |
Using the boundedness of and the absolute convergence, we can estimate upwards the integral
whence is finite and thus converges absolutely. Hence (2) implies
i.e. exists as finite, therefore also
Antithesis: . It implies that there is an such that
If now , then we had
This means that and consequently also would be divergent. Since it is not true, we infer that , i.e. that the assertion (1) is true.
Title | absolute convergence of integral and boundedness of derivative |
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Canonical name | AbsoluteConvergenceOfIntegralAndBoundednessOfDerivative |
Date of creation | 2013-03-22 19:01:28 |
Last modified on | 2013-03-22 19:01:28 |
Owner | pahio (2872) |
Last modified by | pahio (2872) |
Numerical id | 7 |
Author | pahio (2872) |
Entry type | Theorem |
Classification | msc 40A10 |
Related topic | NecessaryConditionOfConvergence |