arithmetic-geometric series


It is well known that a finite geometric seriesMathworldPlanetmath is given by

Gn⁢(q)=∑k=1nqk=q1-q⁢(1-qn),q≠1, (1)

where in general q=r⁢ei⁢θ is complex. When we are dealing with such sums it is common to consider the expression

Hn⁢(q):=∑k=1nk⁢qk,q≠1, (2)

which we shall call an arithmetic-geometric series. Let us derive a formula for Hn⁢(q).

Hn⁢(q)=∑k=1nk⁢qk,q⁢Hn⁢(q)=∑k=1nk⁢qk+1.

Subtracting,

(1-q)⁢Hn⁢(q)=∑k=1nk⁢qk-∑k=1nk⁢qk+1=∑k=1nk⁢qk-∑k=2n+1(k-1)⁢qk=∑k=1nk⁢qk-∑k=2n(k-1)⁢qk-n⁢qn+1.

We will proceed to eliminate the right-hand side sums.

(1-q)⁢Hn⁢(q)=q+∑k=2nqk-n⁢qn+1=∑k=1nqk-n⁢qn+1.

By using (1) and solving for Hn⁢(q), we obtain

Hn(q)=∑k=1nkqk=q(1-q)2(1-qn)-n⁢qn+11-q⋅ (3)

The formula (3) holds in any commutative ring with 1, as long as (1-q) is invertiblePlanetmathPlanetmath. If q is a complex numberMathworldPlanetmathPlanetmath and |q|<1, (3) is the partial sum of the convergent seriesMathworldPlanetmathPlanetmath

H⁢(q)=limn→∞⁡Hn⁢(q)=limn→∞⁡∑k=1nk⁢qk=limn→∞⁡[q(1-q)2⁢(1-qn)-n⁢qn+11-q],

that is,

H⁢(q)=∑k=1∞k⁢qk=q(1-q)2,|q|<1. (4)

This last result giving the sum of a converging arithmetic-geometric series may be, naturally, obtained also from the sum formula of the converging geometric series, i.e.

1+q+q2+q3+…=11-q,

when one differentiates both sides with respect to q and then multiplies them by q:

1+2⁢q+3⁢q2+…=1(1-q)2,
q+2⁢q2+3⁢q3+…=q(1-q)2

(A power series can be differentiated termwise on the open interval of convergence.)

Title arithmetic-geometric series
Canonical name ArithmeticgeometricSeries
Date of creation 2013-03-22 16:02:15
Last modified on 2013-03-22 16:02:15
Owner perucho (2192)
Last modified by perucho (2192)
Numerical id 6
Author perucho (2192)
Entry type Derivation
Classification msc 40C99