Dedekind-finite
A ring is Dedekind-finite if for , whenever implies .
Of course, every commutative ring is Dedekind-finite. Therefore, the theory of Dedekind finiteness is trivial in this case. Some other examples are
-
1.
any ring of endomorphisms over a finite dimensional vector space (over a field)
-
2.
any division ring
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3.
any ring of matrices over a division ring
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4.
finite direct product

of Dedekind-finite rings
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5.
by the last three examples, any semi-simple ring is Dedekind-finite.
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6.
any ring with the property that there is a natural number

such that for every nilpotent element

The finite dimensionality in the first example can not be extended to the infinite![]()
case. Lam in [1] gave an example of a ring that is not Dedekind-finite arising out of the ring of endomorphisms over an infinite dimensional vector space (over a field).
References
- 1 T. Y. Lam, A First Course in Noncommutative Rings, Springer-Verlag, New York (1991).
- 2 T. Y. Lam, Lectures on Modules and Rings, Springer-Verlag, New York (1999).
| Title | Dedekind-finite |
|---|---|
| Canonical name | Dedekindfinite |
| Date of creation | 2013-03-22 14:18:23 |
| Last modified on | 2013-03-22 14:18:23 |
| Owner | CWoo (3771) |
| Last modified by | CWoo (3771) |
| Numerical id | 10 |
| Author | CWoo (3771) |
| Entry type | Definition |
| Classification | msc 16U99 |
| Synonym | von Neumann-finite |