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differentiable function
Let be a function, where and are Banach spaces. For , the function is said to be differentiable at if its derivative exists at that point. Differentiability at implies continuity at . If , then is said to be differentiable on if is differentiable at every point .
For the most common example, a real function is differentiable if its derivative exists for every point in the region of interest. For another common case of a real function of variables (more formally ), it is not sufficient that the partial derivatives exist for to be differentiable. The derivative of must exist in the original sense at every point in the region of interest, where is treated as a Banach space under the usual Euclidean vector norm.
If the derivative of is continuous, then is said to be . If the th derivative of is continuous, then is said to be . By convention, if is only continuous but does not have a continuous derivative, then is said to be . Note the inclusion property . And if the -th derivative of is continuous for all , then is said to be . In other words is the intersection .
Differentiable functions are often referred to as smooth. If is , then is said to be -smooth. Most often a function is called smooth (without qualifiers) if is or , depending on the context.
Mathematics Subject Classification
26A24 Differentiation (functions of one variable): general theory, generalized derivatives, mean-value theorems57R35 Differentiable mappings
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Comments
functions on a fin. dim. vector space
In regards to the point raised in correction number 4.
Let's say V is an n-dimensional, real vector space.
1) Note that V is not a banach space, although it could be made
into one in an infinite number of ways.
2) It is true that V is isomorphic to R^n, in the sense
that there exist linear bijections between V and R^n,
however there is no way to prefer any one such
bijection over another.
We would like to define what it means for a
function f:V -> R to be differentiable, but how
to proceed?
We need a norm for the denominator of our limit
expression, but which norm are we to use?
The fact of the matter is that if f:V->R is differentiable
with respect to one norm, it is differentiable with
respect to all norms. This is an interesting consequence
of the finite-dimensionality of V.
Thus the concept of "differentiable function"
makes sense in the context of "finite dimensional
vector spaces", which is not quite the same context as
"Banach spaces".
A similar phenomenon occurs if we try to topologize
V. The way to proceed is to pick a norm, any norm
and to use that particular norm topology. It doesn't
matter which norm we choose to do this, we get the
same topology regardless. This is, of course,
not true in the infinite-dimensional
setting.
See also
non-Newtonian calculus