equivalence of definitions of -algebra
In this entry, we will prove that the definitions of algebra given in the
main entry are equivalent![]()
.
Theorem 1.
A Banach algebra![]()
with an antilinear involution such that
for all is a -algebra.
Proof.
It follows from the product inequality that
Therefore, . Putting for , we also have . Thus, the involution is an isometry: . So now,
Hence, . ∎
Theorem 2.
A Banach algebra with an antilinear involution such that is a -algebra.
| Title | equivalence of definitions of -algebra |
|---|---|
| Canonical name | EquivalenceOfDefinitionsOfCalgebra |
| Date of creation | 2013-03-22 17:42:27 |
| Last modified on | 2013-03-22 17:42:27 |
| Owner | rspuzio (6075) |
| Last modified by | rspuzio (6075) |
| Numerical id | 4 |
| Author | rspuzio (6075) |
| Entry type | Theorem |
| Classification | msc 46L05 |
| Related topic | HomomorphismsOfCAlgebrasAreContinuous |
| Related topic | CAlgebra |