example of Banach algebra which is not a C*-algebra for any involution
Consider the Banach algebra π={[Ξ»InA0Ξ»In]:Ξ»ββ,AβMatnΓn(β)} with the usual matrix operations and matrix norm, where In denotes the identity matrix in MatnΓn(β).
Claim - π is not a C*-algebra (http://planetmath.org/CAlgebra) for any involution
*.
To prove the above claim we will give a proof of a more general fact about finite dimensional C*-algebras, which clearly shows the for a Banach algebra to be a C*-algebra for some involution.
Theorem - Every finite dimensional C*-algebra is semi-simple, i.e. its Jacobson radical
is {0}.
Proof : Let β¬ be a finite dimensional C*-algebra. Let a be an element of J(β¬), the Jacobson radical of β¬.
J(β¬) is an ideal of β¬, so a*aβJ(β¬).
The Jacobson radical of a finite dimensional algebra is nilpotent, therefore there exists nββ such that (a*a)n=0. Then, by the C* condition and the fact that a*a is selfadjoint,
0=β₯(a*a)2nβ₯=β₯a*aβ₯2n=β₯aβ₯2n+1 |
so a=0 and J(β¬) is trivial. β‘
We now prove the above claim.
Proof of the claim: It is easy to see that
{[0A00]:AβMatnΓn(β)} is the only maximal ideal of π. Therefore the Jacobson radical of π is not trivial.
By the theorem we conclude that there is no involution * that makes π into a C*-algebra.β‘
Remark - It could happen that there were no involutions in π and so the above claim would be uninteresting. Thatβs not the case here. For example, one can see that [ai,j]βΆ[Λa2n+1-j,2n+1-i] defines an involution in π (this is just the taken over the other diagonal of the matrix).
Title | example of Banach algebra which is not a C*-algebra for any involution |
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Canonical name | ExampleOfBanachAlgebraWhichIsNotACalgebraForAnyInvolution |
Date of creation | 2013-03-22 17:25:54 |
Last modified on | 2013-03-22 17:25:54 |
Owner | asteroid (17536) |
Last modified by | asteroid (17536) |
Numerical id | 5 |
Author | asteroid (17536) |
Entry type | Example |
Classification | msc 46L05 |
Defines | finite dimensional C*-algebras are semi-simple |