existence and uniqueness of the gcd of two integers
Theorem.
Given two integers, at least one different from zero, there exists a unique natural number satisfying the definition of the greatest common divisor
.
Proof.
Let a,b∈ℤ, where at least one of a,b is nonzero. First we show existence. Define
S={ma+nb:m,n∈ℤ and ma+nb>0}. Now clearly S is a subset of natural numbers, and S is also nonempty, for depending upon the signs of a and b, we may take m=n=±1 to have ma+nb∈S. So, by the well-ordering principle for natural numbers, S has a smallest element which we denote g.
Note that, by construction, g=m0a+n0b for some m0,n0∈ℤ. We will show that g is a greatest common divisor of a and b. Suppose first that g∤. Then, by the division algorithm for integers, there exist unique , where , such that . By assumption, , so we have
But then is an element of strictly less than , contrary to assumption. Thus it must be that . Similarly it can be shown that . Now suppose is a divisor of both and . Then there exist such that and , and we have
so . Thus is a greatest common divisor of and . To see that is unique, suppose that is also a greatest common divisor of and . Then we have and , whence , and since , . ∎
Title | existence and uniqueness of the gcd of two integers |
---|---|
Canonical name | ExistenceAndUniquenessOfTheGcdOfTwoIntegers |
Date of creation | 2013-03-22 16:28:44 |
Last modified on | 2013-03-22 16:28:44 |
Owner | alozano (2414) |
Last modified by | alozano (2414) |
Numerical id | 5 |
Author | alozano (2414) |
Entry type | Theorem |
Classification | msc 11-00 |
Related topic | GreatestCommonDivisor |
Related topic | DivisibilityInRings |
Related topic | DivisionAlgorithmForIntegers |
Related topic | WellOrderingPrinciple |