existence of adjoints of bounded operators
Let ℋ be a Hilbert space and let T:𝒟(T)⊂ℋ⟶ℋ be a densely defined linear operator
.
Theorem - If T is bounded (http://planetmath.org/ContinuousLinearMapping) then its adjoint T* is everywhere defined and is also bounded.
Proof : Since T is densely defined and bounded, it extends uniquely to a bounded (everywhere defined) linear operator on ℋ, which we denote by ˜T.
For each z∈ℋ, the function f:ℋ⟶ℂ defined by
f(x)=⟨˜Tx,z⟩ defines a bounded linear functional on ℋ. By the Riesz representation theorem
there exists u∈ℋ such that
f(x)=⟨x,u⟩ |
i.e.
⟨˜Tx,z⟩=⟨x,u⟩. |
Since ˜T extends T, we also have that for every z∈ℋ there exists u∈ℋ such that
⟨Tx,z⟩=⟨x,u⟩for everyx∈𝒟(T). |
We conclude that T* is everywhere defined. To see that it is bounded one just needs to check that
sup |
where the last inequality comes from the Cauchy-Schwarz inequality and the fact that is bounded.
Remark - This theorem shows in particular that bounded linear operators have bounded adjoints .
Title | existence of adjoints of bounded operators |
---|---|
Canonical name | ExistenceOfAdjointsOfBoundedOperators |
Date of creation | 2013-03-22 17:33:44 |
Last modified on | 2013-03-22 17:33:44 |
Owner | asteroid (17536) |
Last modified by | asteroid (17536) |
Numerical id | 4 |
Author | asteroid (17536) |
Entry type | Theorem |
Classification | msc 47A05 |
Synonym | bounded operators![]() |