existence of maximal subgroups
Because every finite group![]()
is a finite set
![]()
, every chain of proper subgroups
![]()
of a finite group has a maximal element
![]()
and thus every finite group has
a maximal subgroup. The same applies to maximal normal subgroups.
However, there are infinite groups, even abelian![]()
, with no maximal subgroups and
no maximal normal subgroups. The Prüfer group
(for any prime ) is an example of an abelian group with no maximal subgroups.
As the group is abelian all subgroups![]()
are normal so it also has no maximal
normal subgroups. Such groups fail to fit the hypothesis
![]()
of the Jordan-Hölder decomposition theorem as they do not have the ascending chain condition
![]()
and so we cannot assign a composition series
![]()
to such groups.
This stands in contrast to the category![]()
of unital rings where if one assumes Zorn’s lemma (axiom of choice
![]()
) then one may prove every unital ring
has a maximal ideal
![]()
.
| Title | existence of maximal subgroups |
|---|---|
| Canonical name | ExistenceOfMaximalSubgroups |
| Date of creation | 2013-03-22 16:24:54 |
| Last modified on | 2013-03-22 16:24:54 |
| Owner | Algeboy (12884) |
| Last modified by | Algeboy (12884) |
| Numerical id | 5 |
| Author | Algeboy (12884) |
| Entry type | Example |
| Classification | msc 20E28 |
| Related topic | PropertyOfInfiniteSimpleGroup |
| Related topic | JordanHolderDecomposition |
| Related topic | EveryRingHasAMaximalIdeal |