explicit generators of a quotient polynomial ring associated to a given polynomial


Let k be a field and consider ring of polynomials k⁢[X]. If F⁢(X)∈k⁢[X] and W⁢(X)∈k⁢[X], then we will write W⁢(X)¯ to denote element in k⁢[X]/(F⁢(X)) represented by W⁢(X).

Lemma. Assume, that a1,…,an∈k are different elements and F⁢(X)=(X-a1)⁢⋯⁢(X-an). Let Wi⁢(X)∈k⁢[X] be given by Wi⁢(X)=(X-a1)⁢⋯⁢(X-ai-1)⋅(X-ai+i)⁢⋯⁢(X-an). Then there exist λ1,…,λn∈k such that F⁢(X) divides polynomialMathworldPlanetmathPlanetmathPlanetmath

U⁢(X)=(∑i=1nλi⋅Wi⁢(X))-1.

Proof. Note, that Wi⁢(ai)≠0 for any i. Thus we may define λi=(Wi⁢(ai))-1. Then for any i we have λi⋅Wi⁢(ai)=1, therefore

V⁢(X)=∑i=1nλi⋅Wi⁢(X)

is such that V⁢(ai)=1 for any i. In particular U⁢(ai)=V⁢(ai)-1=0 and thus (X-ai) divides U⁢(X) for any i. This completesPlanetmathPlanetmathPlanetmathPlanetmathPlanetmathPlanetmath the proof. □

Corollary. Under the same assumptionsPlanetmathPlanetmath as in lemma, we have that ideal (W1⁢(X)¯,…,Wn⁢(X)¯) in k⁢[X]/(F⁢(X)) is equal to k⁢[X]/(F⁢(X)).

Proof. Indeed, all we need to show is that we can generate 1¯. Lemma implies, that there is V⁢(X)∈k⁢[X] such that

(∑i=1nλi⋅Wi⁢(X))-1=F⁢(X)⋅V⁢(X).

Now, after aplying quotientPlanetmathPlanetmath homomorphismPlanetmathPlanetmathPlanetmathPlanetmathPlanetmathPlanetmathPlanetmathPlanetmath to both sides we have

∑i=1nλi⋅Wi⁢(X)¯=1¯.

This completes the proof. □

Remark. This gives us an explicit formula for generatorsPlanetmathPlanetmathPlanetmath of k⁢[X]/(F⁢(X)). In particular the dimension over k of this ring is at most deg⁢F⁢(X). It can be shown that actualy it is equal, even if F⁢(X) is arbitrary.

Title explicit generators of a quotient polynomial ring associated to a given polynomial
Canonical name ExplicitGeneratorsOfAQuotientPolynomialRingAssociatedToAGivenPolynomial
Date of creation 2013-03-22 19:10:01
Last modified on 2013-03-22 19:10:01
Owner joking (16130)
Last modified by joking (16130)
Numerical id 6
Author joking (16130)
Entry type Derivation
Classification msc 11C08
Classification msc 12E05
Classification msc 13P05