Fréchet space
We consider two classes of topological vector spaces![]()
, one more general
than the other. Following Rudin [1] we will define a Fréchet space
to be an element of the smaller class, and refer to an instance of the
more general class as an F-space. After giving the
definitions, we will explain why one definition is stronger than the
other.
Definition 1.
An F-space is a complete topological vector space whose topology![]()
is
induced by a translation
![]()
invariant metric. To be more precise, we say
that is an F-space if there exists a metric function
such that
and such that the collection![]()
of balls
is a base for the topology of .
Note 1.
Recall that a topological vector space is a uniform space.
The hypothesis![]()
that is complete
is formulated in reference to this
uniform structure. To be more precise, we say that a sequence is Cauchy if for every neighborhood of the
origin there exists an such that
for all . The completeness condition then takes
the usual form of the hypothesis that all Cauchy sequences
possess a
limit point
![]()
.
Note 2.
It is customary to include the hypothesis that is
Hausdorff in the definition of a topological vector space.
Consequently, a Cauchy sequence in a complete topological space
will have a unique limit.
Note 3.
Since is assumed to be complete, the pair
is a complete metric space. Thus, an equivalent![]()
definition of
an F-space is that of a vector space
![]()
equipped with a complete, translation-invariant (but not necessarily homogeneous
(http://planetmath.org/NormedVectorSpace)) metric, such that the operations
![]()
of scalar
multiplication and vector addition are continuous
![]()
with respect to this
metric.
Definition 2.
A Fréchet space is a complete topological vector space (either real
or complex) whose topology is induced by a countable![]()
family of
semi-norms. To be more precise, there exist semi-norm functions
such that the collection of all balls
is a base for the topology of .
Proposition 1
Let be a complete topological vector space. Then, is a Fréchet space if and only if it is a locally convex F-space.
Proof.
First, let us show that a Fréchet space is a locally convex F-space,
and then prove the converse![]()
. Suppose then that is Fréchet. The
semi-norm balls are convex; this follows directly from the semi-norm
axioms. Therefore is locally convex. To obtain the desired
distance function we set
| (1) |
We now show that satisfies the metric axioms. Let such that be given. Since is Hausdorff, there is at least one seminorm such
Hence .
Let be three real numbers such that
A straightforward calculation shows that
| (2) |
as well. The above trick underlies the definition (1) of our metric function. By the seminorm axioms we have that
for all . Combining this with (1) and
(2) yields the triangle inequality![]()
![]()
for .
Next let us suppose that is a locally convex F-space, and prove that it is Fréchet. For every let be an open convex neighborhood of the origin, contained inside a ball of radius about the origin. Let be the seminorm with as the unit ball. By definition, the unit balls of these seminorms give a neighborhood base for the topology of . QED.
References
-
1
W.Rudin, Functional Analysis

.
| Title | Fréchet space |
|---|---|
| Canonical name | FrechetSpace |
| Date of creation | 2013-03-22 13:06:10 |
| Last modified on | 2013-03-22 13:06:10 |
| Owner | rmilson (146) |
| Last modified by | rmilson (146) |
| Numerical id | 51 |
| Author | rmilson (146) |
| Entry type | Definition |
| Classification | msc 57N17 |
| Classification | msc 54E50 |
| Classification | msc 52A07 |
| Related topic | TopologicalVectorSpace |
| Related topic | HausdorffSpaceNotCompletelyHausdorff |
| Defines | F-space |