generalized intermediate value theorem
Theorem.
Let be a continuous function![]()
with a connected space and a totally ordered set
![]()
in the order topology. If and lies between and , then there exists such that .
Proof.
The sets and are disjoint open subsets of in the subspace topology, and they are both non-empty, as is contained in one and is contained in the other. If , then constitutes a of the space , contradicting the hypothesis![]()
that is the continuous image of the connected space . Thus there must exist such that .
∎
This version of the intermediate value theorem reduces to the familiar one of http://planetmath.org/node/7599real analysis when is taken to be a closed interval![]()
in and is taken to be .
References
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1
J. Munkres, Topology

, 2nd ed. Prentice Hall, 1975.
| Title | generalized intermediate value theorem |
|---|---|
| Canonical name | GeneralizedIntermediateValueTheorem |
| Date of creation | 2013-03-22 17:17:44 |
| Last modified on | 2013-03-22 17:17:44 |
| Owner | azdbacks4234 (14155) |
| Last modified by | azdbacks4234 (14155) |
| Numerical id | 8 |
| Author | azdbacks4234 (14155) |
| Entry type | Theorem |
| Classification | msc 26A06 |
| Related topic | OrderTopology |
| Related topic | TotalOrder |
| Related topic | Continuous |
| Related topic | ConnectedSpace |
| Related topic | ConnectednessIsPreservedUnderAContinuousMap |