Hogatt’s theorem
Hogatt’s theorem states that every positive integer can be expressed as
a sum of distinct Fibonacci numbers![]()
.
For any positive integer, , there exists a unique positive integer
so that . We proceed by strong induction![]()
on . For , the property is true as are themselves Fibonacci numbers. Suppose and that every integer less than is a sum of distinct Fibonacci numbers. Let be the largest positive integer such that . We first note that if then
giving us a contradiction![]()
. Hence and consequently the positive integer can be expressed as a sum of distinct Fibonacci numbers. Moreover, this sum does not contain the term as .
Hence, is a sum of distinct Fibonacci numbers and Hogatt’s theorem is proved by induction.
| Title | Hogatt’s theorem |
|---|---|
| Canonical name | HogattsTheorem |
| Date of creation | 2013-03-22 13:43:24 |
| Last modified on | 2013-03-22 13:43:24 |
| Owner | mathcam (2727) |
| Last modified by | mathcam (2727) |
| Numerical id | 8 |
| Author | mathcam (2727) |
| Entry type | Theorem |
| Classification | msc 11B39 |
| Related topic | FibonacciSequence |