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# homomorphisms from fields are either injective or trivial

Suppose $F$ is a field, $R$ is a ring, and $\phi\colon F\rightarrow R$ is a homomorphism of rings. Then $\phi$ is either trivial or injective.

###### Proof.

We use the fact that kernels of ring homomorphism are ideals. Since $F$ is a field, by the above result, we have that the kernel of $\phi$ is an ideal of the field $F$ and hence either empty or all of $F$. If the kernel is empty, then since a ring homomorphism is injective iff the kernel is trivial, we get that $\phi$ is injective. If the kernel is all of $F$, then $\phi$ is the zero map from $F$ to $R$. ∎

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