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infinitely-differentiable function that is not analytic
If , then we can certainly write a Taylor series for . However, analyticity requires that this Taylor series actually converge (at least across some radius of convergence) to . It is not necessary that the power series for converge to , as the following example shows.
Let
Then , and for any , (see below). So the Taylor series for around 0 is 0; since for all , clearly it does not converge to .
Proof that
Let be polynomials, and define
Then, for ,
Computing (e.g. by applying LβHΓ΄pitalβs rule), we see that .
Define . Applying the above inductively, we see that we may write . So , as required.
Major Section:
Reference
Type of Math Object:
Example
Parent:
Mathematics Subject Classification
30B10 Power series (including lacunary series)26A99 None of the above, but in MSC2010 section 26Axx
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