integrals of even and odd functions
Theorem. Let the real function f be Riemann-integrable (http://planetmath.org/RiemannIntegrable) on [-a,a]. If f is an
-
•
even function
, then ∫a-af(x)𝑑x= 2∫a0f(x)𝑑x,
-
•
odd function, then ∫a-af(x)𝑑x= 0.
Of course, both cases concern the zero map which is both
.
Proof. Since the definite integral is additive with respect to the interval of integration, one has
I:= |
Making in the first addend the substitution and swapping the limits of integration one gets
Using then the definitions of even (http://planetmath.org/EvenoddFunction) () and odd (http://planetmath.org/EvenoddFunction) () function yields
which settles the equations of the theorem.
Title | integrals of even and odd functions |
Canonical name | IntegralsOfEvenAndOddFunctions |
Date of creation | 2014-03-13 16:17:44 |
Last modified on | 2014-03-13 16:17:44 |
Owner | pahio (2872) |
Last modified by | pahio (2872) |
Numerical id | 10 |
Author | pahio (2872) |
Entry type | Theorem |
Classification | msc 26A06 |
Synonym | integral of odd function |
Synonym | integral of even function |
Related topic | DefiniteIntegral |
Related topic | ChangeOfVariableInDefiniteIntegral |
Related topic | ExampleOfUsingResidueTheorem |
Related topic | FourierSineAndCosineSeries |
Related topic | IntegralOverAPeriodInterval |