integration under integral sign


Let

I⁢(α)=∫abf⁢(x,α)⁢𝑑x.

where  f⁢(x,α) is continuousMathworldPlanetmath in the rectangle

a≦x≦b,α1≦α≦α2.

Then  α↦I⁢(α)  is continuous and hence integrable (http://planetmath.org/RiemannIntegrable) on the interval  α1≦α≦α2;  we have

∫α1α2I⁢(α)⁢𝑑α=∫α1α2(∫abf⁢(x,α)⁢𝑑x)⁢𝑑α.

This is a double integral over a in the x⁢α-plane, whence one can change the order of integration (http://planetmath.org/FubinisTheorem) and accordingly write

∫α1α2(∫abf⁢(x,α)⁢𝑑x)⁢𝑑α=∫ab(∫α1α2f⁢(x,α)⁢𝑑α)⁢𝑑x.

Thus, a definite integral depending on a parametre may be integrated with respect to this parametre by performing the integration under the integral sign.

Example.  For being able to evaluate the improper integral

I=∫0∞e-a⁢x-e-b⁢xxdx  (a>0,b>0),

we may interprete the integrand as a definite integral:

e-a⁢x-e-b⁢xx=/α=ba⁡e-α⁢xx=∫abe-α⁢x⁢𝑑α.

Accordingly, we can calculate as follows:

I  =∫0∞(∫abe-α⁢x⁢𝑑α)⁢𝑑x
 =∫ab(∫0∞e-α⁢x⁢𝑑x)⁢𝑑α
 =∫ab(/x=0∞-e-α⁢xα)⁢𝑑α
 =∫ab1α⁢𝑑α=/ab⁡ln⁡α
 =ln⁡ba
Title integration under integral sign
Canonical name IntegrationUnderIntegralSign
Date of creation 2013-03-22 18:46:27
Last modified on 2013-03-22 18:46:27
Owner pahio (2872)
Last modified by pahio (2872)
Numerical id 5
Author pahio (2872)
Entry type Theorem
Classification msc 26A42
Related topic FubinisTheorem
Related topic DifferentiationUnderIntegralSign
Related topic RelativeOfExponentialIntegral