lattice of topologies
Let X be a set. Let L be the set of all topologies on X. We may order L by inclusion. When 𝒯1⊆𝒯2, we say that 𝒯2 is finer (http://planetmath.org/Finer) than 𝒯1, or that 𝒯2 refines 𝒯1.
Theorem 1.
L, ordered by inclusion, is a complete lattice.
Proof.
Clearly L is a partially ordered set when ordered by ⊆. Furthermore, given any family of topologies 𝒯i on X, their intersection
⋂𝒯i also defines a topology on X. Finally, let ℬi’s be the corresponding subbases for the 𝒯i’s and let ℬ=⋃ℬi. Then 𝒯 generated by ℬ is easily seen to be the supremum
of the 𝒯i’s.
∎
Let L be the lattice of topologies on X. Given 𝒯i∈L, 𝒯:= is called the common refinement of . By the proof above, this is the coarsest topology that is than each .
If is non-empty with more than one element, is also an atomic lattice. Each atom is a topology generated by one non-trivial subset of (non-trivial being non-empty and not ). The atom has the form , where .
Remark. In general, a lattice of topologies on a set is a sublattice of the lattice of topologies (mentioned above) on .
Title | lattice of topologies |
---|---|
Canonical name | LatticeOfTopologies |
Date of creation | 2013-03-22 16:54:42 |
Last modified on | 2013-03-22 16:54:42 |
Owner | CWoo (3771) |
Last modified by | CWoo (3771) |
Numerical id | 8 |
Author | CWoo (3771) |
Entry type | Definition |
Classification | msc 54A10 |
Related topic | Coarser |
Defines | common refinement |