lattice of topologies
Let be a set. Let be the set of all topologies![]()
on . We may order by inclusion. When , we say that is finer (http://planetmath.org/Finer) than , or that refines .
Theorem 1.
, ordered by inclusion, is a complete lattice![]()
.
Proof.
Clearly is a partially ordered set![]()
when ordered by . Furthermore, given any family of topologies on , their intersection
![]()
also defines a topology on . Finally, let ’s be the corresponding subbases for the ’s and let . Then generated by is easily seen to be the supremum
![]()
of the ’s.
∎
Let be the lattice of topologies on . Given , is called the common refinement of . By the proof above, this is the coarsest topology that is than each .
If is non-empty with more than one element, is also an atomic lattice. Each atom is a topology generated by one non-trivial subset of (non-trivial being non-empty and not ). The atom has the form , where .
Remark. In general, a lattice of topologies on a set is a sublattice of the lattice of topologies (mentioned above) on .
| Title | lattice of topologies |
|---|---|
| Canonical name | LatticeOfTopologies |
| Date of creation | 2013-03-22 16:54:42 |
| Last modified on | 2013-03-22 16:54:42 |
| Owner | CWoo (3771) |
| Last modified by | CWoo (3771) |
| Numerical id | 8 |
| Author | CWoo (3771) |
| Entry type | Definition |
| Classification | msc 54A10 |
| Related topic | Coarser |
| Defines | common refinement |