minimality property of Fourier coefficients
Let be a Riemann integrable periodic real function with period and a positive integer. Among all “trigonometric polynomials”
the polynomial with the coefficients and being the Fourier coefficients
and
for the Fourier series of produces the minimal value of the mean square deviation
Proof. For any fixed number , it’s a question of giving the least value to the definite integral
(1) |
Expanding and integrating termwise yields
Here, we have the Fourier coefficients
Furthermore,
and
Using all these we can write
Adding and subtracting still the sum yields finally the form
The three first addends of this sum do not depend on the choice of the quantities and . The other addends are non-negative, and their sum is minimal, equal 0, when
Accordingly, the mean square deviation , i.e. (1), is minimal when one uses the Fourier coefficients. Q.E.D.
References
- 1 N. Piskunov: Diferentsiaal- ja integraalarvutus kõrgematele tehnilistele õppeasutustele. Kirjastus Valgus, Tallinn (1966).
Title | minimality property of Fourier coefficients |
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Canonical name | MinimalityPropertyOfFourierCoefficients |
Date of creation | 2013-03-22 18:22:00 |
Last modified on | 2013-03-22 18:22:00 |
Owner | pahio (2872) |
Last modified by | pahio (2872) |
Numerical id | 13 |
Author | pahio (2872) |
Entry type | Theorem |
Classification | msc 42A16 |
Classification | msc 42A10 |
Related topic | CommonFourierSeries |
Related topic | UniquenessOfFourierExpansion |