Multifuncoid has atomic arguments
A counter-example against this conjecture have been found. See \hrefhttp://www.mathematics21.org/algebraic-general-topology.htmlAlgebraic General Topology.
Prerequisites: \hrefhttp://www.mathematics21.org/algebraic-general-topology.htmlAlgebraic General Topology.
Conjecture. L∈[f]⇒[f]∩∏i∈dom𝔄atomsLi≠∅ for every pre-multifuncoid f of the form whose elements are atomic posets.
A weaker conjecture: It is true for forms whose elements are powersets.
The following is an attempted (partial) proof:
If arityf=0 our theorem is trivial, so let arityf≠0. Let ⊑ is a well-ordering of arityf with greatest element m.
Let Φ is a function which maps non-least elements of posets into atoms under these elements and least elements into themselves. (Note that Φ is defined on least elements only for completeness, Φ is never taken on a least element in the proof below.) \colorbrown [TODO: Fix the ”universal set” paradox here.]
Define a transfinite sequence a by transfinite induction with the formula
ac=Φ⟨f⟩c(a|X(c)∖{c}∪L|(arityf)∖X(c)).
Let bc=a|X(c)∖{c}∪L|(arityf)∖X(c). Then ac=Φ⟨f⟩cbc.
Let us prove by transfinite induction ac∈atomsLc. ac=Φ⟨f⟩cL|(arityf)∖{c}⊑⟨f⟩cL|(arityf)∖{c}. Thus ac⊑Lc. [TODO: Is it true for pre-multifuncoids?]
The only thing remained to prove is that ⟨f⟩cbc≠0
that is ⟨f⟩c(a|X(c)∖{c}∪L|(arityf)∖X(c))≠0 that is y≭.
Title | Multifuncoid has atomic arguments |
---|---|
Canonical name | MultifuncoidHasAtomicArguments |
Date of creation | 2014-12-14 21:09:54 |
Last modified on | 2014-12-14 21:09:54 |
Owner | porton (9363) |
Last modified by | porton (9363) |
Numerical id | 2 |
Author | porton (9363) |
Entry type | Conjecture |
Classification | msc 54J05 |
Classification | msc 54A05 |
Classification | msc 54D99 |
Classification | msc 54E05 |
Classification | msc 54E17 |
Classification | msc 54E99 |