Multifuncoid has atomic arguments


A counter-example against this conjecture have been found. See \hrefhttp://www.mathematics21.org/algebraic-general-topology.htmlAlgebraic General Topology.

Prerequisites: \hrefhttp://www.mathematics21.org/algebraic-general-topology.htmlAlgebraic General Topology.

Conjecture. L∈[f]⇒[f]∩∏i∈dom⁡𝔄atomsLi≠∅ for every pre-multifuncoid f of the form whose elements are atomic posets.

A weaker conjecture: It is true for forms whose elements are powersets.

The following is an attempted (partial) proof:

If arity⁡f=0 our theorem is trivial, so let arity⁡f≠0. Let ⊑ is a well-ordering of arity⁡f with greatest element m.

Let Φ is a function which maps non-least elements of posets into atoms under these elements and least elements into themselves. (Note that Φ is defined on least elements only for completeness, Φ is never taken on a least element in the proof below.) \colorbrown [TODO: Fix the ”universal set” paradoxMathworldPlanetmath here.]

Define a transfinite sequence a by transfinite inductionMathworldPlanetmath with the formulaMathworldPlanetmathPlanetmath ac=Φ⁢⟨f⟩c⁢(a|X⁢(c)∖{c}∪L|(arity⁡f)∖X⁢(c)).

Let bc=a|X⁢(c)∖{c}∪L|(arity⁡f)∖X⁢(c). Then ac=Φ⁢⟨f⟩c⁢bc.

Let us prove by transfinite induction ac∈atoms⁡Lc. ac=Φ⁢⟨f⟩c⁢L|(arity⁡f)∖{c}⊑⟨f⟩c⁢L|(arity⁡f)∖{c}. Thus ac⊑Lc. [TODO: Is it true for pre-multifuncoids?]

The only thing remained to prove is that ⟨f⟩c⁢bc≠0

that is ⟨f⟩c⁢(a|X⁢(c)∖{c}∪L|(arity⁡f)∖X⁢(c))≠0 that is y≭⟨f⟩c⁢bc.

Title Multifuncoid has atomic arguments
Canonical name MultifuncoidHasAtomicArguments
Date of creation 2014-12-14 21:09:54
Last modified on 2014-12-14 21:09:54
Owner porton (9363)
Last modified by porton (9363)
Numerical id 2
Author porton (9363)
Entry type Conjecture
Classification msc 54J05
Classification msc 54A05
Classification msc 54D99
Classification msc 54E05
Classification msc 54E17
Classification msc 54E99