perpendicular bisector
Let be a line segment in a plane (we are assuming the Euclidean plane). A bisector of is any line that passes through the midpoint of . A perpendicular bisector of is a bisector that is perpendicular to .
It is an easy exercise to show that a line is a perpendicular bisector of iff every point lying on is equidistant from and . From this, one concludes that the perpendicular bisector of a line segment is always unique.
A basic way to construct the perpendicular bisector given a line segment using the standard ruler and compass construction is as follows:
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1.
use a compass to draw the circle centered at point with radius the length of , by fixing one end of the compass at and the movable end at ,
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2.
similarly, draw the circle centered at with the same radius as above, with the compass fixed at and movable at ,
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3.
and intersect at two points, say (why?)
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4.
with a ruler, draw the line ,
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5.
then is the perpendicular bisector of .
(Note: we assume that there is always an ample supply of compasses and rulers of varying sizes, so that given any positive real number , we can find a compass that opens wider than and a ruler that is longer than ).
One of the most common use of perpendicular bisectors is to find the center of a circle constructed from three points in a Euclidean plane:
Given three non collinear points in a Euclidean plane, let be the unique circle determined by . Then the center of is located at the intersection of the perpendicular bisectors of and .
Title | perpendicular bisector |
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Canonical name | PerpendicularBisector |
Date of creation | 2013-03-22 16:29:03 |
Last modified on | 2013-03-22 16:29:03 |
Owner | CWoo (3771) |
Last modified by | CWoo (3771) |
Numerical id | 18 |
Author | CWoo (3771) |
Entry type | Definition |
Classification | msc 51M15 |
Classification | msc 51N20 |
Classification | msc 51N05 |
Synonym | center normal |
Related topic | Circumcircle |
Defines | bisector |