prime element is irreducible in integral domain


Theorem.
Proof.

Let D be an integral domain, and let a∈D be a prime element. Assume a=b⁢c for some b,c∈D.

Clearly a∣bc, so since a is prime, a∣b or a∣c. Without loss of generality, assume a∣b, and say a⁢t=b for some t∈D.

If 1 is the unity of D, then

1⁢b=b=a⁢t=(b⁢c)⁢t=b⁢(c⁢t).

Since D is an integral domain, b can be cancelled, giving 1=c⁢t, so c is a unit. ∎

Title prime element is irreducible in integral domain
Canonical name PrimeElementIsIrreducibleInIntegralDomain
Date of creation 2013-03-22 17:15:29
Last modified on 2013-03-22 17:15:29
Owner me_and (17092)
Last modified by me_and (17092)
Numerical id 7
Author me_and (17092)
Entry type Theorem
Classification msc 13G05
Related topic IrreducibleOfAUFDIsPrime