prime element is irreducible in integral domain
Theorem.
Every prime element of an integral domain
is irreducible.
Proof.
Let D be an integral domain, and let a∈D be a prime element. Assume a=bc for some b,c∈D.
Clearly a∣bc, so since a is prime, a∣b or a∣c. Without loss of generality, assume a∣b, and say at=b for some t∈D.
If 1 is the unity of D, then
1b=b=at=(bc)t=b(ct). |
Since D is an integral domain, b can be cancelled, giving 1=ct, so c is a unit. ∎
Title | prime element is irreducible in integral domain |
---|---|
Canonical name | PrimeElementIsIrreducibleInIntegralDomain |
Date of creation | 2013-03-22 17:15:29 |
Last modified on | 2013-03-22 17:15:29 |
Owner | me_and (17092) |
Last modified by | me_and (17092) |
Numerical id | 7 |
Author | me_and (17092) |
Entry type | Theorem |
Classification | msc 13G05 |
Related topic | IrreducibleOfAUFDIsPrime |