proof of cofactor expansion


Let M∈m⁢a⁢tN⁢(K) be a n×n-matrix with entries from a commutativePlanetmathPlanetmathPlanetmathPlanetmath field K. Let e1,…,en denote the vectors of the canonical basis of Kn. For the proof we need the following

Lemma: Let Mi⁢j* be the matrix generated by replacing the i-th row of M by ej. Then

det⁡Mi⁢j*=(-1)i+j⁢det⁡Mi⁢j

where Mi⁢j is the (n-1)×(n-1)-matrix obtained from M by removing its i-th row and j-th column.

Proof.

By adding appropriate of the i-th row of Mi⁢j* to its remaining rows we obtain a matrix with 1 at position (i,j) and 0 at positions (k,j) (k≠i). Now we apply the permutationMathworldPlanetmath

(12)∘(23)∘…∘((i-1)⁢i)

to rows and

(12)∘(23)∘…∘((j-1)⁢j)

to columns of the matrix. The matrix now looks like this:

  • •

    Row/column 1 is the vector e1;

  • •

    under row 1 and right of column 1 is the matrix Mi⁢j.

Since the determinantMathworldPlanetmath has changed its sign i+j-2 times, we have

det⁡Mi⁢j*=(-1)i+j⁢det⁡Mi⁢j.

Note also that only those permutations π∈Sn are for the computation of the determinant of Mi⁢j* where π⁢(i)=j. ∎

Now we start out with

det⁡M =∑π∈Snsgn⁢π⁢(∏j=1nmj⁢π⁢(j))
=∑k=1nmi⁢k⁢(∑π∈Sn∣π(i)=ksgn⁢π⁢(∏1≤j≤imj⁢π⁢(j))⋅1⋅(∏i≤j≤nmj-π⁢(j))).

From the previous lemma, it follows that the associated with Mi⁢k is the determinant of Mi⁢j*. So we have

det⁡M=∑k=1nMi⁢k⁢((-1)i+k⁢det⁡Mi⁢k).
Title proof of cofactor expansion
Canonical name ProofOfCofactorExpansion
Date of creation 2013-03-22 13:22:08
Last modified on 2013-03-22 13:22:08
Owner Thomas Heye (1234)
Last modified by Thomas Heye (1234)
Numerical id 13
Author Thomas Heye (1234)
Entry type Proof
Classification msc 15A15
Synonym Laplace expansionPlanetmathPlanetmath