proof of counting theorem
Let N be the cardinality of the set of all the couples (g,x) such that g⋅x=x. For each g∈G, there exist stabg(X) couples with g as the first element, while for each x, there are |Gx| couples with x as the second element. Hence the following equality holds:
N=∑g∈Gstabg(X)=∑x∈X|Gx|. |
From the orbit-stabilizer theorem it follows that:
N=|G|∑x∈X1|G(x)|. |
Since all the x belonging to the same orbit G(x) contribute with
|G(x)|1|G(x)|=1 |
in the sum, then ∑x∈X1/|G(x)| precisely equals the number of distinct orbits s. We have therefore
∑g∈Gstabg(X)=|G|s, |
which proves the theorem.
Title | proof of counting theorem |
---|---|
Canonical name | ProofOfCountingTheorem |
Date of creation | 2013-03-22 12:47:07 |
Last modified on | 2013-03-22 12:47:07 |
Owner | n3o (216) |
Last modified by | n3o (216) |
Numerical id | 5 |
Author | n3o (216) |
Entry type | Proof |
Classification | msc 20M30 |