proof of division algorithm for integers
Let a,b integers (b>0). We want to express a=bq+r for some integers q,r with 0≤r<b and that such expression is unique.
Consider the numbers
…,a-3b,a-2b,a-b,a,a+b,a+2b,a+3b,… |
From all these numbers, there has to be a smallest non negative one. Let it be r. Since r=a-qb for some q,11For example, if r=a+5b then q=-5. we have a=bq+r. And, if r≥b then r wasn’t the smallest non-negative number on the list, since the previous (equal to r-b) would also be non-negative. Thus 0≤r<b.
So far, we have proved that we can express a asbq+r for some pair of integers q,r such that 0≤r<b. Now we will prove the uniqueness of such expression.
Let q′ and r′ another pair of integers holding a=bq′+r′ and 0≤r′<b. Suppose r≠r′. Since r′=a-bq′ is a number on the list, cannot be smaller or equal than r and thus r<r′. Notice that
0<r′-r=(a-bq′)-(a-bq)=b(q-q′) |
so b divides r′-r which is impossible since 0<r′-r<b. We conclude that r′=r. Finally, if r=r′ then a-bq=a-bq′ and therefore q=q′. This concludes the proof of the uniqueness part.
Title | proof of division algorithm for integers |
---|---|
Canonical name | ProofOfDivisionAlgorithmForIntegers |
Date of creation | 2013-03-22 13:01:11 |
Last modified on | 2013-03-22 13:01:11 |
Owner | drini (3) |
Last modified by | drini (3) |
Numerical id | 4 |
Author | drini (3) |
Entry type | Proof |
Classification | msc 11A51 |