proof of identity theorem of power series
We start by proving a more modest result. Namely, we show that, under the hypotheses of the theorem we are trying to prove, we can conclude that .
Let be chosen such that both series converge when .
From the set of points at which the two power series
![]()
are equal, we may
choose a sequence such that
-
•
for all .
-
•
exists and equals .
-
•
for all .
.
Since power series converge uniformly, we may interchange the limit with the summation.
Because for all , this means that .
We will now prove that for all by
an induction![]()
argument
. The intial step with
is, of course, the result demonstrated above.
Assume that for all less than
some integer . Then we have
for all . Pulling out a common factor and relabelling the index, we have
Because , the factor will not equal zero, so we may cancel it:
By our weaker result, we have . Hence, by induction, we have for all .
| Title | proof of identity theorem of power series |
|---|---|
| Canonical name | ProofOfIdentityTheoremOfPowerSeries |
| Date of creation | 2013-03-22 16:47:38 |
| Last modified on | 2013-03-22 16:47:38 |
| Owner | rspuzio (6075) |
| Last modified by | rspuzio (6075) |
| Numerical id | 7 |
| Author | rspuzio (6075) |
| Entry type | Proof |
| Classification | msc 30B10 |
| Classification | msc 40A30 |