proof of identity theorem of power series
We start by proving a more modest result. Namely, we show that, under the hypotheses of the theorem we are trying to prove, we can conclude that .
Let be chosen such that both series converge when . From the set of points at which the two power series are equal, we may choose a sequence such that
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for all .
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exists and equals .
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for all .
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Since power series converge uniformly, we may interchange the limit with the summation.
Because for all , this means that .
We will now prove that for all by an induction argument. The intial step with is, of course, the result demonstrated above. Assume that for all less than some integer . Then we have
for all . Pulling out a common factor and relabelling the index, we have
Because , the factor will not equal zero, so we may cancel it:
By our weaker result, we have . Hence, by induction, we have for all .
Title | proof of identity theorem of power series |
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Canonical name | ProofOfIdentityTheoremOfPowerSeries |
Date of creation | 2013-03-22 16:47:38 |
Last modified on | 2013-03-22 16:47:38 |
Owner | rspuzio (6075) |
Last modified by | rspuzio (6075) |
Numerical id | 7 |
Author | rspuzio (6075) |
Entry type | Proof |
Classification | msc 30B10 |
Classification | msc 40A30 |