proof of Marty’s theorem
Let be a region with and let be the curves connecting the points . Then we have:
Thus is Lipschitz continuous and thus is equicontinuous. By the Ascoli-ArzelÃÂ Theorem we conclude that is normal.
(ii) Now assume to be normal. Define:
Let be compact. To obtain contradiction![]()
assume is not uniformly bounded on .
But then there exists a sequence such that:
Since is normal for each let there be a neighbourhood such that converges normally to a meromorphic function . But from we see that converges normally on . Since is compact it can be covered by finitely many sets . We conclude that must be bounded
on and obtain a contradiction. ∎
| Title | proof of Marty’s theorem |
|---|---|
| Canonical name | ProofOfMartysTheorem |
| Date of creation | 2013-03-22 18:23:11 |
| Last modified on | 2013-03-22 18:23:11 |
| Owner | karstenb (16623) |
| Last modified by | karstenb (16623) |
| Numerical id | 4 |
| Author | karstenb (16623) |
| Entry type | Proof |
| Classification | msc 30D30 |