proof of theorem about cyclic subspaces
We first prove the case r=2. The ⊆ inclusion is clear, since the right side is a T-invariant subspace that contains v1+v2.
For the other inclusion, it is sufficient to show that v1,v2∈Z(v1+v2,T). The idea is that the action of T on v1+v2 can ”isolate” the two summands if their annihilator polynomials are coprime. Let’s write mi for mvi.
Since (m1,m2)=1, there exist polynomials p and q such that
pm1+qm2=1 | (1) |
this is Bézout’s lemma (or the Euclidean algorithm, or the fact that k[X] is a principal ideal domain
).
Now pm1(T) is the projection from Z(v1,T)⊕Z(v2,T) to Z(v2,T):
(pm1)(T)v1=p(T)m1(T)v1=p(T)0=0 | (2) |
(by assumption that m1 is the annihilator polynomial of v1) and
(pm1)(T)=1-(qm2)(T) | (3) |
(by choice of p and q), so
(pm1)(T)v2=v2-q(T)m2(T)v2=v2-q(T)0=v2 | (4) |
Any subspace that is invariant under T is also invariant under polynomials of T. Therefore, the preceding equations show that v2=(pm1)(T)(v1+v2)∈Z(v1+v2,T). By symmetry, we also get that v1∈Z(v1+v2,T).
For the last claim, we note that the annihilator polynomial m of Z(v1,T)⊕Z(v2,T) is the least common multiple of m1 and m2 (that m is a multiple of m1 follows from the fact that m must annihilate v1, and the set of polynomials that annihilate v1 is the ideal generated by m1). Since m1 and m2 are coprime, the lcm is just their product.
That concludes the proof for r=2. If r is arbitrary, we can simply apply the r=2 case inductively. We only have to check that the coprimality condition is preserved under applying the r=2 case to i=1,2. But it is well-known that if p,q,r (in k[X] or in any principal ideal domain) are pairwise coprime, then pq and r are also coprime.
Title | proof of theorem about cyclic subspaces |
---|---|
Canonical name | ProofOfTheoremAboutCyclicSubspaces |
Date of creation | 2013-03-22 17:32:53 |
Last modified on | 2013-03-22 17:32:53 |
Owner | FunctorSalad (18100) |
Last modified by | FunctorSalad (18100) |
Numerical id | 7 |
Author | FunctorSalad (18100) |
Entry type | Proof |
Classification | msc 15A04 |