proof of the uniformization theorem
Our proof relies on the well-known Newlander-Niremberg theorem which implies, in particular, that any Riemmanian metric on an oriented 2-dimensional real manifold defines a unique analytic structure.
We will merely use the fact that H1(X,ℝ)=0. If X is compact, then X is a complex curve of genus 0, so X≃ℙ1. On the other hand, the elementary Riemann mapping theorem says that an open set Ω⊂ℂ with H1(Ω,ℝ)=0 is either equal to ℂ or biholomorphic to the unit disk. Thus, all we have to show is that a non compact Riemann surface X with H1(X,ℝ)=0 can be embedded in the complex plane ℂ.
Let Ων be an exhausting sequence of relatively compact connected open sets with smooth boundary in X. We may assume that X∖Ων has no relatively compact connected components, otherwise we “fill the holes” of Ων by taking the union with all such components. We let Yν be the double of the manifold with boundary (ˉΩν,∂Ων), i.e. the union of two copies of ˉΩν with opposite orientations and the boundaries identified. Then Yν is a compact oriented surface without boundary.
Fact: we have H1(Yν,ℝ)=0. We postpone the proof of this fact to the end of the present paragraph and we continue with the proof of the uniformization theorem.
Extend the almost complex structure of ˉΩν in an arbitrary way to Yν, e.g. by an extension of a Riemmanian metric. Then Yν becomes a compact Riemann surface of genus 0, thus Yν≃ℙ1 and we obtain in particular a holomorphic embedding Φν:Ων→ℂ. Fix a point a∈Ω0 and a non zero linear form ξ*∈TaX. We can take the composition of Φν with an affine linear map ℂ→ℂ so that Φν(a)=0 and dΦν(a)=ξ*. By the well-known properties of injective holomorphic maps, (Φν) is then uniformly bounded on every small disk centered at a, thus also on every compact subset of X by a connectedness argument. Hence (Φν) has a subsequence converging towards an injective holomorphic map Φ:X→ℂ.
Proof of the ”fact”: Let us first compute the cohomology with compact support H1c(Ων,ℝ). Let u be a closed 1-form with compact support in Ων. By Poincaré duality H1c(X,ℝ)=0, so u=df for some ”test” function f∈𝒟(X). As df=0 on a neighborhood of X∖Ων and as all connected components of this set are non compact, f must be equal to the constant zero near X∖Ων. Hence u=df is the zero class in H1c(Ων,ℝ) and we get H1c(Ων,ℝ)=H1(Ων,ℝ)=0. The exact sequence of the pair (ˉΩν,∂Ωnu) yelds
ℝ=H0(ˉΩν,ℝ)→H0(∂Ων,ℝ)→H1(ˉΩν,∂Ων;ℝ)≃H1c(Ων,ℝ)=0, |
thus H0(∂Ων,ℝ)=ℝ. Finally, the Mayer-Vietoris sequence applied to small neighborhoods of the two copies of ˉΩν in Yν gives an exact sequence
H0(ˉΩν,ℝ)⊕2→H0(∂Ων,ℝ)→H1(Yν,ℝ)→H1(ˉΩν,ℝ)⊕2=0 |
where the first map is onto. Hence H1(Yν,ℝ)=0.
References
J.-P. Demailly, Complex Analytic and Algebraic Geometry
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Title | proof of the uniformization theorem |
---|---|
Canonical name | ProofOfTheUniformizationTheorem |
Date of creation | 2013-03-22 15:37:50 |
Last modified on | 2013-03-22 15:37:50 |
Owner | Simone (5904) |
Last modified by | Simone (5904) |
Numerical id | 14 |
Author | Simone (5904) |
Entry type | Proof |
Classification | msc 30F20 |
Classification | msc 30F10 |