tensor product of subspaces of vector spaces
Proposition. Let be vector spaces over a field . Moreover let , be subspaces. Then .
Proof. The inclusion ,,” is obvious. We will show the inclusion ,,”.
Let and be bases of and respectively. Moreover let be a completion of given basis of to the basis of , i.e. is a basis of . Analogously let be a completion of a basis of to the basis of . Then each element can be uniquely written in a form
Assume that Let and . Consider the following linear map: such that if and if . Analogously we define . Then we combine these two mappings into one, i.e.
Furthermore we have
Note that since , then and thus
Similarly we obtain that all and are equal to . Thus
which completes the proof.
Title | tensor product of subspaces of vector spaces |
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Canonical name | TensorProductOfSubspacesOfVectorSpaces |
Date of creation | 2013-03-22 18:49:16 |
Last modified on | 2013-03-22 18:49:16 |
Owner | joking (16130) |
Last modified by | joking (16130) |
Numerical id | 4 |
Author | joking (16130) |
Entry type | Theorem |
Classification | msc 15A69 |