tensor product of subspaces of vector spaces


PropositionPlanetmathPlanetmath. Let V,W be vector spacesMathworldPlanetmath over a field k. Moreover let A⊆V, B⊆W be subspacesPlanetmathPlanetmath. Then V⊗B∩A⊗W=A⊗B.

Proof. The inclusion ,,⊇” is obvious. We will show the inclusion ,,⊆”.

Let {ei}i∈I and {ej′}j∈P be bases of A and B respectively. Moreover let {ei}i∈I′ be a completion of given basis of A to the basis of V, i.e. {ei}i∈I∪I′ is a basis of V. Analogously let {ej′}j∈P′ be a completion of a basis of B to the basis of W. Then each element q∈V⊗W can be uniquely written in a form

q=∑i∈I,j∈Pαi,j⁢ei⊗ej′+∑i∈I′,j∈Pβi,j⁢ei⊗ej′+
+∑i∈I,j∈P′δi,j⁢ei⊗ej′+∑i∈I′,j∈P′γi,j⁢ei⊗ej′.

Assume that q∈V⊗B∩A⊗W. Let i∈I′ and j∈P′. Consider the following linear map: fi:V→k such that fi⁢(et)=1 if i=t and fi⁢(et)=0 if i≠t. Analogously we define gj:W→k. Then we combine these two mappings into one, i.e.

fi⊗gj:V⊗W→k;
(fi⊗gj)⁢(v⊗w)=fi⁢(v)⁢gj⁢(w).

Furthermore we have

(fi⊗gj)⁢(q)=γi,j.

Note that since q∈V⊗B, then (fi⊗gj)⁢(q)=0 and thus

γi,j=0.

Similarly we obtain that all βi,j and δi,j are equal to 0. Thus

q=∑i∈I,j∈Pαi,j⁢ei⊗ej′∈A⊗B,

which completesPlanetmathPlanetmathPlanetmath the proof. □

Title tensor product of subspaces of vector spaces
Canonical name TensorProductOfSubspacesOfVectorSpaces
Date of creation 2013-03-22 18:49:16
Last modified on 2013-03-22 18:49:16
Owner joking (16130)
Last modified by joking (16130)
Numerical id 4
Author joking (16130)
Entry type Theorem
Classification msc 15A69