Tychonoff’s theorem
Let be a family of nonempty topological spaces![]()
. The product space (see product topology)
is compact if and only if each of the spaces is compact.
Not surprisingly, if is infinite![]()
, the proof requires the Axiom of Choice
![]()
. Conversely, one can show that Tychonoff
’s theorem implies that any product
of nonempty sets is nonempty, which is one form of the Axiom of Choice.
| Title | Tychonoff’s theorem |
|---|---|
| Canonical name | TychonoffsTheorem |
| Date of creation | 2013-03-22 12:05:14 |
| Last modified on | 2013-03-22 12:05:14 |
| Owner | matte (1858) |
| Last modified by | matte (1858) |
| Numerical id | 12 |
| Author | matte (1858) |
| Entry type | Theorem |
| Classification | msc 54D30 |
| Synonym | Tichonov’s theorem |
| Related topic | Compact |