Weierstrass double series theorem


If the complex functions  f0,f1,f2,…  are holomorphic in the disc  |z-z0|<r  and thus

fn⁢(z)=∑ν=0∞an⁢ν⁢(z-z0)ν,an⁢ν=fn(ν)⁢(z0)ν! ∀n,ν (1)

in this disc, and if the function series

∑n=0∞fn=f0+f1+f2+… (2)

converges uniformly to the function F in each disc  |z-z0|≦ϱ  where  0<ϱ<r,  then also all the series

∑n=0∞an⁢ν=a0⁢ν+a1⁢ν+a2⁢ν+… (ν=0, 1, 2,…) (3)

converge, and in the disc  |z-z0|<r  one has

F⁢(z)=∑ν=0∞Aν⁢(z-z0)ν (4)

where the Aνs are the sums of the series (3).

Proof.  Apparently, the series (2) converges uniformly also in every closed sub-disc of the open disc   |z-z0|<r.  Therefore the theorem 2 in the entry “theorems on complex function series (http://planetmath.org/TheoremsOnComplexFunctionSeries)” says that the sum F⁢(z) is holomorphic in  |z-z0|<r  and

F(ν)(z)=f0(ν)(z0)+f1(ν)(z0)+f2(ν)(z0)+… (ν=0, 1, 2,…).

Theorem 3 in the same entry thus guarantees that F⁢(z) has the Taylor expansionMathworldPlanetmath of the form (4) wherein

Aν=1ν!F(ν)(z0) (ν=0, 1, 2,…).

According to theorem 2 in the same entry the series (2) may be differentiated termwise,

Aν=1ν!⁢∑n=0∞fn(ν)⁢(z0)=∑n=0∞1ν!⁢fn(ν)⁢(z0)=∑n=0∞an⁢ν

Q.E.D.

Note.  In Weierstrass double series theoremMathworldPlanetmath it’s a question of changing the summing :

F⁢(z)=f0⁢(z)+f1⁢(z)+…+fn⁢(z)+…==[a00+a01⁢(z-z0)+a02⁢(z-z0)2+…+a0⁢ν⁢(z-z0)ν+…]+[a10+a11⁢(z-z0)+a12⁢(z-z0)2+…+a1⁢ν⁢(z-z0)ν+…]+[a20+a21⁢(z-z0)+a22⁢(z-z0)2+…+a2⁢ν⁢(z-z0)ν+…]…⁢…+[an⁢0+an⁢1⁢(z-z0)+an⁢2⁢(z-z0)2+…+an⁢ν⁢(z-z0)ν+…]⋯⋯                    ¯=A0+A1⁢(z-z0)+A2⁢(z-z0)2+…+Aν⁢(z-z0)ν+…
Title Weierstrass double series theorem
Canonical name WeierstrassDoubleSeriesTheorem
Date of creation 2013-03-22 16:48:15
Last modified on 2013-03-22 16:48:15
Owner pahio (2872)
Last modified by pahio (2872)
Numerical id 7
Author pahio (2872)
Entry type Theorem
Classification msc 30B10
Classification msc 40A05
Classification msc 30D30
Related topic TheoremsOnComplexFunctionSeries