proof of product rule
By simply calculating, we have for all values of in the domain of and that
The key argument here is the next to last line, where we have used the fact that both and are differentiable, hence the limit can be distributed across the sum to give the desired equality.
|Title||proof of product rule|
|Date of creation||2013-03-22 12:28:00|
|Last modified on||2013-03-22 12:28:00|
|Last modified by||mathcam (2727)|