# $\eta (1)=ln2$

Since $\zeta (1)=\mathrm{\infty}$, $\eta (1)$ cannot be computed as indicated in the Dirichlet eta function^{} entry. $\eta (1)=\mathrm{ln}2$ which is the alternate harmonic series of order 1.

Title | $\eta (1)=ln2$ |
---|---|

Canonical name | eta1ln2 |

Date of creation | 2013-03-22 16:10:30 |

Last modified on | 2013-03-22 16:10:30 |

Owner | dextercioby (12657) |

Last modified by | dextercioby (12657) |

Numerical id | 5 |

Author | dextercioby (12657) |

Entry type | Example |

Classification | msc 11M41 |