On the Residue Theorem


On the Residue TheoremMathworldPlanetmath Swapnil Sunil Jain December 26, 2006

On the Residue Theorem

The Residue Theorem

If γ is a simply closed contour and f is analytic within the region bounded by γ except for some finite number of poles z0,z1,…,zn then

∫γf⁢(z)⁢𝑑z = 2⁢π⁢i⁢∑k=0nR⁢e⁢sz=zk⁢f⁢(z)

where R⁢e⁢sz=zk⁢f⁢(z) is the reside of f⁢(z) at zk.

Calculating Residues

The Residue of f⁢(z) at a particular pole p depends on the characteristicPlanetmathPlanetmath of the pole.

For a single pole p, R⁢e⁢sz=p⁢f⁢(z)=limz→p⁡[(z-p)⁢f⁢(z)]

For a double pole p, R⁢e⁢sz=p⁢f⁢(z)=limz→p⁡[dd⁢z⁢(z-p)2⁢f⁢(z)]

For a n-tuple pole p, R⁢e⁢sz=p⁢f⁢(z)=limz→p⁡[1(n-1)!⁢d(n-1)d⁢z(n-1)⁢(z-p)n⁢f⁢(z)]

Evaluation of Real-Valued Definite Integrals

We can use the Residue theorem to evaluate real-valued definite integral of the form

∫02⁢πf⁢(sin⁡(n⁢θ),cos⁡(n⁢θ))⁢𝑑θ (1)

If we let z=ei⁢θ, then d⁢zd⁢θ=i⁢ei⁢θ=i⁢z which implies that d⁢θ=d⁢zi⁢z. Then using the identityPlanetmathPlanetmath cos⁡(n⁢θ)=12⁢(zn+z-n) and sin⁡(n⁢θ)=12⁢i⁢(zn-z-n), we can re-write (1) as

∫γg⁢(z)⁢d⁢zi⁢z (2)

where g⁢(z)=f⁢(12⁢i⁢(zn-z-n),12⁢(zn+z-n)) and γ is a contour that traces the unit circle. Then, by the Residue theorem, (2) is equal to

2⁢π⁢i⁢∑k=0nR⁢e⁢sz=zk⁢(g⁢(z)i⁢z)=2⁢π⁢ii⁢∑k=0nR⁢e⁢sz=zk⁢(g⁢(z)z)=2⁢π⁢∑k=0nR⁢e⁢sz=zk⁢(g⁢(z)z)

where zk are the poles of g⁢(z)z.

Title On the Residue Theorem
Canonical name OnTheResidueTheorem1
Date of creation 2013-03-11 19:29:41
Last modified on 2013-03-11 19:29:41
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