converse of Darboux’s theorem (analysis) is not true
Darboux’ theorem says that, if has an antiderivative, than has to satisfy the intermediate value property, namely, for any , for any number with or , there exists a such that . With this theorem, we understand that if does not satisfy the intermediate value property, then no function satisfies on .
Now, we will give an example to show that the converse is not true, i.e., a function that satisfies the intermediate value property might still have no antiderivative.
Let
First let us see that satisfies the intermediate value property. Let . If or , the property is satisfied, since is continuous on and . If , we have and . Let be between and . Let for some large enough such that . Then , and since is continuous on , we must have a with .
Assume, for a contradiction that there exists a differentiable function such that on . Then consider the function which is defined on . We have on , and since it is a an open connected set, we must have on for some . But then, we have
and
which contradicts the differentiability of at .
Title | converse of Darboux’s theorem (analysis) is not true |
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Canonical name | ConverseOfDarbouxsTheoremanalysisIsNotTrue |
Date of creation | 2013-03-22 17:33:51 |
Last modified on | 2013-03-22 17:33:51 |
Owner | Gorkem (3644) |
Last modified by | Gorkem (3644) |
Numerical id | 6 |
Author | Gorkem (3644) |
Entry type | Example |
Classification | msc 26A06 |