First Isomorphism Theorem for quivers
Let and be quivers. Assume, that is a morphism of quivers. Define an equivalence relation on as follows: for any and any we have
It can be easily checked that is an equivalence relation on .
Using standard techniques we can prove the following:
First Isomorphism Theorem for quivers. The mapping
(where on the left side we have the quotient quiver (http://planetmath.org/QuotientQuiver) and on the right side the image of a quiver (http://planetmath.org/SubquiverAndImageOfAQuiver)) given by
is an isomorphism of quivers.
Proof. It easily follows from the definition of that is a well-defined morphism of quivers. Thus it is enough to show, that is both ,,onto” and ,,1-1” (in the sense that corresponding components of are).
-
1.
We will show, that is onto, i.e. both are onto. Let and . By definition
for some , . It follows that
which completes this part.
- 2.
This completes the proof.
Title | First Isomorphism Theorem for quivers |
---|---|
Canonical name | FirstIsomorphismTheoremForQuivers |
Date of creation | 2013-03-22 19:17:25 |
Last modified on | 2013-03-22 19:17:25 |
Owner | joking (16130) |
Last modified by | joking (16130) |
Numerical id | 5 |
Author | joking (16130) |
Entry type | Definition |
Classification | msc 14L24 |