n-dimensional isoperimetric inequality


Isoperimetric inequalitiesMathworldPlanetmath for 2 and 3 dimensionsPlanetmathPlanetmath are generalized here to n dimensions. First, the n-dimensional ball is shown to have the greatest volume for a given (n-1)-surface area. Then, the volume and area of the n-ball are used to establish the n-dimensional isoperimetric inequality.

1 THE GREATEST N-VOLUME

We shall use cartesian coordinatesMathworldPlanetmath based on the ortho-normal vector system B¯1,B¯2, etc… An (n-1) surface S is defined by a functionMathworldPlanetmath of n coordinatesMathworldPlanetmathPlanetmath equated to zero. On this surface, any coordinate can be considered as a function of all the others. Let us take the last one xn, as a function of x1,x2xn-1, and call it z for brevity. This surface is the envelope of an n-dimensional solid of volume V:

V=V𝑑x1𝑑x2𝑑z=Sz𝑑x1𝑑x2𝑑xn-1

We are going to maximize V, subject to the condition that the surface S has a given area A:

S=S𝑑s=A

The infinitesimalMathworldPlanetmath surface element ds is (see the annex):

S=S1+Z12++Zn-12𝑑x1𝑑xn-1

Zi are the partial derivativesMathworldPlanetmath of z with respect to xi. This surface constraint is handled with the help of a Lagrange multiplier R which allows us to maximize a single function F:

I=SF𝑑x1𝑑xn-1=S(z+R1+Z12++Zn-12)𝑑x1𝑑xn-1

The solution to this variational problem is given by the n-1 Euler-Lagrange equations:

Fz-xi(FZi)=0

In our case, they turn to be:

xi(Zi1+Z12++Zn-12)=1R

After a first integration, and squaring, we have:

Zi21+Z12++Zn-12=(xi-ai)2R2

Summing all these equations together, after some algebra, we get:

Zi=zxi=xi-aiR2-(x1-a1)2--(xn-1-an-1)2

This system is easily integrated and gives exactly the equation on an n-ball, which is therefore a stationary point of the functional I. Since the minimum volume is obviously zero for a flat solid, the n-ball has necessarily the maximum volume.

2 THE ISOPERIMETRIC INEQUALITY

The volume BVn of an n-ball of radius R is (ref 1):

BVn=πn2Γ(n2+1)Rn

Γ is Euler’s gamma functionDlmfDlmfMathworldPlanetmath. Since this volume is obviously the integralDlmfPlanetmath of the surface from 0 to R, the surface is the derivative of the volume with respect to R:

BAn=2πn2Γ(n2)Rn-1

Eliminating the radius R between these two equations, we get:

(BVn)n-1(BAn)n=π-n2[Γ(n2)]n2n[n2Γ(n2)]n-1=Γ(n2+1)(nπ)n

This equality holds for an n-ball. The volume Vn of an arbitrary solid of area An cannot be greater than the volume BVn of an n-ball with the same area; therefore the following inequalityMathworldPlanetmath holds:

(Vn)n-1(An)nΓ(n2+1)(nπ)n

This is the so-called isoperimetric inequality for n dimensions.

3 ANNEX: N-DIMENSIONAL PARALLELEPIPED

The infinitesimal surface element of an n-dimensional solid is in fact the volume of an infinitesimal (n-1)-parallelepipedMathworldPlanetmath. This volume (ref 2) is the square rootMathworldPlanetmath of the Gram determinantMathworldPlanetmath of the edge vectors U¯1,U¯2U¯n-1. The elements of this determinantDlmfMathworldPlanetmath are the dot productsMathworldPlanetmath of the edge vectors:

Gij=U¯iU¯j

Let P be the position vector of a point in the (n-1) dimensional enveloppe of the solid. δ¯i is the infinitesimal displacement we get by varying the coordinate xi by dxi and keeping all the other (n-2) independent variables fixed. Only the last coordinate z varies to maintain the new position into the envelope:

δ¯i=dxiB¯i+dzB¯n=dxi(B¯i+zxiB¯n)=dxi(B¯i+ZiB¯n)

Zi is a shortcut for the partial derivative of z with respect to xi. The (n-1) infinitesimal vectors δ¯i define an (n-1)-parallelepiped and its Gram determinant is:

Gij=δ¯iδ¯j=(δij+ZiZj)dxidxj

δij is the Kronecker symbolMathworldPlanetmath. In the determinant, dxi appears in one row and one column, so that it can be factored out twice. Therefore, the volume of the (n-1)-parallelepiped δ¯i, or the surface element ds is:

ds=δij+ZiZjdx1dx2dxn-1

The determinant of the matrix H defined by Hij=δij+ZiZj is the product of its eigenvaluesMathworldPlanetmathPlanetmathPlanetmathPlanetmath. For any (n-1)-vector W¯ we have:

HW¯=W¯+(Z¯W¯)Z¯

Z¯ being the (n-1)-vector (Z1,Z2Zn-1). If W¯ is orthogonalMathworldPlanetmathPlanetmath to Z¯, HW¯=W¯ and its eigenvalue is 1. But there are (n-2) such vectors, so the determiant is the last eignevalue for W¯=Z¯: HZ¯=(1+|Z|2)Z¯. Finally:

ds=Z12+Z22++Zn-12dx1dx2dxn-1

References

  • 1 Eric Weinstein - HypersphereMathworldPlanetmath
    http://mathworld.wolfram.com/Hypersphere.html
    An elegant proof of the hypersphere volume formula.
  • 2 Nils Barth - The Gramian and K-Volume in N-Space
    http://www.jyi.org/volumes/volume2/issue1/articles/barth.html
Title n-dimensional isoperimetric inequality
Canonical name NdimensionalIsoperimetricInequality
Date of creation 2013-03-22 19:20:01
Last modified on 2013-03-22 19:20:01
Owner dh2718 (16929)
Last modified by dh2718 (16929)
Numerical id 4
Author dh2718 (16929)
Entry type Theorem
Classification msc 51M16
Classification msc 51M25