example of pseudometric space


Let X=ℝ2 and consider the function d:X×X to the non-negative real numbers given by

d⁢((x1,x2),(y1,y2))=|x1-y1|.

Then d⁢(x,x)=|x1-x1|=0, d⁢(x,y)=|x1-y1|=|y1-x1|=d⁢(y,z) and the triangle inequalityMathworldMathworldPlanetmathPlanetmath follows from the triangle inequality on ℝ1, so (X,d) satisfies the defining conditions of a pseudometric space.

Note, however, that this is not an example of a metric space, since we can have two distinct points that are distance 0 from each other, e.g.

d⁢((2,3),(2,5))=|2-2|=0.

Other examples:

  • •

    Let X be a set, x0∈X, and let F⁢(X) be functions X→R. Then d⁢(f,g)=|f⁢(x0)-g⁢(x0)| is a pseudometric on F⁢(X) [1].

  • •

    If X is a vector space and p is a seminorm over X, then d⁢(x,y)=p⁢(x-y) is a pseudometric on X.

  • •

    The trivial pseudometric d⁢(x,y)=0 for all x,y∈X is a pseudometric.

References

  • 1 S. Willard, General Topology, Addison-Wesley, Publishing Company, 1970.
Title example of pseudometric space
Canonical name ExampleOfPseudometricSpace
Date of creation 2013-03-22 14:40:24
Last modified on 2013-03-22 14:40:24
Owner mathcam (2727)
Last modified by mathcam (2727)
Numerical id 6
Author mathcam (2727)
Entry type Example
Classification msc 54E35
Related topic Seminorm
Related topic VectorSpace
Related topic MetricSpace
Related topic Metric
Defines trivial pseudometric